| | #include <iostream> |
| | #include <numeric> |
| | #include <vector> |
| | using namespace std; |
| |
|
| | int curr_sum, best_len; |
| | vector<int> divisors, curr, best_ans; |
| |
|
| | int maxsteps = 0; |
| | int steps = 0; |
| |
|
| | void rec(int P) { |
| | steps++; |
| | if (P == 1) { |
| | int len = curr.size() + (41 - curr_sum); |
| | if (len < best_len) { |
| | best_len = len; |
| | best_ans = curr; |
| | } |
| | return; |
| | } |
| | for (int d : divisors) { |
| | if (P % d == 0 && curr_sum + d <= 41) { |
| | curr.push_back(d); |
| | curr_sum += d; |
| | rec(P / d); |
| | curr_sum -= d; |
| | curr.pop_back(); |
| | } |
| | } |
| | } |
| |
|
| | void solve() { |
| | int P; |
| | cin >> P; |
| | if (P == 1) { |
| | best_ans.assign(41, 1); |
| | } else { |
| | divisors.clear(); |
| | |
| | for (int i = 2; i <= 41; i++) { |
| | if (P % i == 0) { |
| | divisors.push_back(i); |
| | } |
| | } |
| | curr.clear(); |
| | steps = 0; |
| | curr_sum = 0; |
| | best_ans.clear(); |
| | best_len = (int)1e9; |
| | rec(P); |
| | if (steps > maxsteps) { |
| | maxsteps = steps; |
| | cerr << P << endl; |
| | } |
| | } |
| | if (!best_ans.empty()) { |
| | int best_sum = accumulate(best_ans.begin(), best_ans.end(), 0); |
| | for (; best_sum < 41; best_sum++) { |
| | best_ans.push_back(1); |
| | } |
| | cout << " " << best_ans.size(); |
| | for (int f : best_ans) { |
| | cout << " " << f; |
| | } |
| | } else { |
| | cout << " -1"; |
| | } |
| | } |
| |
|
| | int main() { |
| | int T; |
| | cin >> T; |
| | for (int t = 1; t <= T; t++) { |
| | cout << "Case #" << t << ":"; |
| | solve(); |
| | cout << endl; |
| | } |
| | cerr << maxsteps; |
| | return 0; |
| | } |